$\frac{1}{\cot^2x\csc x}=\sin x\tan^2x$
$x^2+x\frac{1}{4}$
$\frac{dy}{dx}=-0.22m$
$-12y-8y$
$\left(-8\right)-\left(-5\right)+\left(-2\right)-\left(-7\right)$
$\left(-14\right)+\left(-7\right)+\left(+3\right)-\left(-8\right)$
$\frac{3a}{2}x\frac{6}{3a}$
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