$\lim_{x\to-4}\left(\frac{x^3+64}{2x+8}\right)$
$\frac{1}{\left(x-1\right)^{\:3}}$
$6-4\cdot6$
$u^2+42u=0$
$\left(-12\right)\left(-45\right)$
$\int\left(3\sin\left(x-2\right)^2\right)\cos\left(x-2\right)dx$
$2x-3y+4x-y+5x$
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