$12m^3n^4\:\:6m^8n^2$
$\frac{12-\tan\theta}{12\csc\theta-\sec\theta}$
$x\frac{dy}{dx}+2xy=x^2$
$\left(4-8\right)\::2-\left(-9+12\right)\::3$
$\frac{4x^3-14x^2-10x+4}{2x-4}$
$-9\cos\left(x\right)+54\cos\left(x\right)^2-3$
$-3\left(x-2\right)^{\frac{4}{5}}+29=-19$
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