$\frac{dy}{dt}=-e^{-t}y^2$
$tanx=-6$
$\lim_{x\to4}\left(\frac{x^2-16}{x^2+4x}\right)$
$\tan\left(2x\right)=-1.125$
$6.1\cdot10^5$
$x^2-4x+4=25$
$\int\frac{2}{\left(1-x^2\right)}dx$
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