$\int_{-6}^6\left(\frac{5}{6+2x^2}\right)dx$

$-18+\left|-10\right|$

$\sin^2\left(x\right)-3\cos^2\left(x\right)=1-4\cos^2\left(x\right)$

$\left(2x^{a-1}+3y^{1-a}\right)^5$

$-4-9-2+8+4+3-1$

$\frac{2\tan\left(3a\right)}{1+\tan^23a}$

$\lim_{x\to\infty}\:\frac{0^{x+1}}{1+0^x}$