$\left(z-\sqrt{z}\right)\left(3+8\sqrt[3]{z^2}\right)$
$x^4-25x^2+144$
$\frac{3x-6}{2x+2}\ge3$
$\sqrt{3^2}$
$\int sen^6y\:dy$
$\frac{x^2}{3}+\frac{-x^2}{3}$
$\frac{dy}{dx}=\left(1+y^2\right)x^2$
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