$3xy\:4x\:-1\:y\:4\:$
$y^2-6y=0$
$8\left(3x\:+\:7\right)$
$\int\left(x^3-2x\right)\log\left(x\right)dx$
$\frac{5}{9}+3.25+7$
$\left(6x+2\right)^3$
$y'+2y=8$
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