$-3\sin\left(t\right)=15\cos\left(t\right)\sin\left(t\right)$
$\left(7a^2b^3+5ab^2\right)^2$
$x^3-10x+3$
$\cot x\left(1+\sin x\right)-\cos^2x\cdot\sec x$
$\frac{3}{2+4x}$
$\frac{\left(x+5\right)}{3}\ge\frac{\left(4-2x\right)}{-5}$
$64-z^3$
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