$\int\left(\frac{2x-5}{3+\left(x+1\right)^2}\right)dx$
$\frac{9^2-81}{12^2-5\left(12\right)-84}$
$3x-\frac{5}{6}=\frac{13}{6}$
$-9\:\left(3w\:+\:7\right)$
$\left(2a-b^2+3\right)^2$
$3x^{2}+12x-13$
$x-y+z=1$
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