$\left(2y-3x\right)^5$
$4\ln\left(x-3\right)=20$
$\frac{dy}{dx}+\frac{1}{x}y=x^3sen\left(2x\right)$
$\left(9+3m\right)\left(3m-9\right)$
$\frac{du}{dv}=e^u$
$\left(\frac{1}{x}+12y^2x\right)dx+\left(12yx^2+siny\right)dy=0$
$225x^2+30x+1$
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