$\lim_{x\to-4}\left(2x^2\right)$
$x^3+2x\cdot4$
$x^2+7x-12\:\left(x+2\right)$
$\lim_{x\to\infty}\frac{45x^3+9x^2-6x}{25-9x^2}$
$2cot\left(2x\right)=\frac{cos\:x}{sin\:x}-\:\frac{sin\:x}{cos\:x}$
$1+2+3+4+5+6+7+8+9$
$\sin^2\left(x\right)+\cos^2\left(x\right)=\tan$
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