$\left(9s\cdot2s\right)^3$
$\left(-4n\right)\cdot\left(-3n^2\right)$
$\frac{\frac{3.99}{3.99+1}-\frac{4}{5}}{3.99-4}$
$\lim_{x\to\infty}\left(x-1\right)x^2$
$\frac{6-2x}{3+x}>2$
$\sqrt[4]{b^7}m^3$
$\frac{\int x^{3}-2x+4}{x+2}dx$
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