$-3x^2:x$
$\sqrt{1+\sqrt{x^4-x^2}}=x$
$\left(\tan\left(x\right)+1\right)^2+\left(\tan\left(x\right)-1\right)^2+\tan\left(x\right)^2$
$\frac{9}{-3}$
$\left(x+7\right)\left(x-9\right)$
$\left(3x^5+2x^2\right)\left(3x^5+2x^2\right)$
$12z\:+92yr9\:+56xz6\:-\:34z\:+87yr9\:-\:24xz6$
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