$y'\:=\:6x\:-\:xy\:-\:y\:+\:6$
$4x^2+16x=8$
$100x-125=-325$
$2x+16x-8x+24x-2x$
$3x+2^2$
$\frac{1}{4}\infty^{-\frac{3}{2}}$
$\left(xy-6z^2\right)^2$
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