$x^2=2.x$
$\int\sqrt{x}\left(1-\sqrt{x}+\sqrt[3]{x^4}\right)dx$
$\tan\left(x\right)+\left(-1-\tan\left(x\right)^2\right)\tan\left(x\right)=-\tan\left(x\right)^3$
$x^2\sqrt{x^2}$
$\lim_{x\to\infty}\left(\frac{3x}{\sqrt{9x^2+1}}\right)$
$5x+3=-27$
$8x^6\:+\:16x^3\:+\:32x^7$
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