$f^2+3f+4$
$\left(2a^2+9\right)^2$
$\lim_{x\to0}\left(\frac{4^x+2^x}{6^x}\right)$
$\left(-250.000\right)\:\left(-85.000\right)\:\left(-65.000\right)\:\left(-90.000\right)$
$\left(\frac{2x^{-2}}{4y^{-1}}\right)^{-3}$
$\frac{9x^2+27x}{3x+1}$
$7x^2+x-10-2x\cdot1$
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