$\frac{x^6}{4}-6x^3y+36y^2$
$-6+0+-1+-3$
$-2+6x\le28$
$4+2-8$
$\int\frac{x^2-2x+3}{\left(x+2\right)\left(x-1\right)}dx$
$\int\frac{\left(5x^2+3\right)}{x^3+x^2-2x}dx$
$20^2+2\left(60\right)^2+3^2$
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