$\frac{x^2}{3\:-\:x}$
$2x^2-6x-8=0$
$\sin\left(4\cdot x+1\right)$
$\int\left(x^3+3x\right)^8\left(x^2+1\right)dx$
$m^6m^6-21-54$
$5m+6m=22$
$\lim_{x\to\infty}\left(1+\frac{3}{x}\right)^{5x}$
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