$\lim_{x\to0}\left(\frac{\sqrt{x^2-4}}{x-2}\right)$
$\frac{dy}{dx}=\frac{x^3}{2y^2}$
$\left(-4v^{-3}\right)^4$
$\lim_{x\to0}\left(\frac{x^2-2x}{x^2+x}\right)$
$2+4x<4-6x$
$\left(\frac{x-y}{3}\right)^3$
$\left(p^5+2q^2\right)^3$
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