$3x^2+3x-18=0$
$\lim_{x\to0}\left(\frac{ln\left(1+4x^2\right)}{x^2}\right)$
$\left(3a^{-2}+\frac{1}{3}\right)\left(-\frac{3}{a^2}+\frac{1}{3}\right)$
$\sec\left(x\right)=-1.5799$
$\frac{d}{dx}\sqrt[4]{x^4+16}$
$x+8=3x+4$
$y'\:=\:x^3y^{-2}$
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