$\lim\:_{x\to\:\:64}\left(\frac{\sqrt{x}-8}{\sqrt[3]{x}-4}\right)$
$\frac{3x-5}{x+2}\ge-\frac{1}{3}$
$5ab^22$
$3b-3-7b-7$
$706-50x\:+x^2$
$y^1+3y=x+e^{-x}$
$\frac{z^2z^4}{z^3z^{-1}}$
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