$\frac{4x+2\le x\:}{6x-5<x+1}$
$y=\tan\left(8x^2-x\right)$
$14c^{-2}$
$\frac{\csc\left(x\right)}{\cot\left(x\right)\tan\left(x\right)}=\cos\left(x\right)$
$10m^2n^4-16m^8$
$\:2x\:tanh\:\left(\frac{2x-2}{3x+2}\right)$
$-26-\left(-5\right)^2$
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