$x^4+16x^2+16$

$\left(3x^2+4xy-2\right)+\left(2x^2+6y^2\right)y'=0$

$\lim_{x\to0}\frac{2e^x-2x-2}{x^2}$

$3x-8\le\frac{7}{3}x-5$

$\frac{dy}{dx}=-\frac{6\left(x+1\right)}{2y-9}$

$6\left(2\right)+3\left(2^2\right)\left(5\right)+5\left(5\right)-3\left(2\right)\left(5^3\right)$

$3\:+5\:+3+\:7+\:10\:+15+\:6+\:10+\:12+\:13+10\:+8\:+12+\:5+\:9+\:11+\:8+\:9+\:9+\:2+12+\:11+\:15+\:14+\:6\:+10+\:7+\:6+\:4+\:8$