$\lim_{x\to\infty}\left(\left(4x^2-1\right)\left(\ln\left(\frac{2x+1}{2x-1}\right)^2\right)\right)$
$2\left(2x^2+49\right)$
$-26+12+14-26-30+7-40+46+12$
$24y^2-6z^2$
$\frac{21}{3}-\frac{20}{5}$
$-23xyz-7xyz$
$0.02\cdot5$
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