$\frac{\cos\left(x\right)\left(1-\sin\left(x\right)\right)}{\cos\left(x^2\right)}=\frac{1-\sin\left(x\right)}{\cos\left(x\right)}$
$\left(2x-3y\right)\left(x-y\right)$
$x^2+12>8x$
$-16-4x^6$
$-1+2+3-1$
$3x+69=180$
$5-7+19-20+4-3+10$
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