$-1729\cdot1$
$x^2+9<3$
$\left(\frac{3x^{\text{4}}}{m^6}\right)^3$
$dy=3\left(x^2-1\right)dx$
$\sin\:\left(360^{\circ\:\:}-\theta\:\right)=-sin\theta\:$
$\lim_{x\to0}\:\frac{1}{x\tan\left(x\right)}\:+\:\frac{1}{x^2}$
$4\cos\left(x\right)^2-4=-4\sin\left(x\right)^2$
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