$\int\frac{x+1}{\left(3x^2+6x-7\right)^8}dx$
$\lim_{x\to\pi}\left(2e^x\cos\left(x\right)\right)$
$2\cos\left(x\right)-\frac{1}{\cos\left(x\right)}$
$1-7+2$
$-\sqrt{121}+15$
$53^3-43^{-2}-2+6-2^{-2}-7-2^3$
$\frac{12}{4}$
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