$\frac{\left(6y^3\right)^4}{2y^5}$
$4x+35x+6$
$\left\{2\left(x-5\right)-3\left(2-2x\right)<0\right\}$
$x^2+15x+8x+120$
$\lim_{x\to4.1}\left(\frac{x^2-16}{x+4}\right)$
$2x-9=-5$
$6x^3+12x^2+6x$
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