$2x^2+x+3x^3$
$6x-12+\frac{1}{4}x^2-7x+8$
$5\cdot\left(-2\right)-3\cdot\left(1\right)-5\cdot2+7$
$\left[15\:+\:3\left(2\right)\:-\:0\right]0$
$5-2.\left[x-1+2\left(x-1\right)\right]=1$
$\int\frac{\left(1\right)}{x^2-1}dx$
$-5+\left(3-5\right)^2-4\left(2-5\right)$
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