$-16x^2-64x+40$
$\left(\frac{a^2}{6}-m^3\right)\left(\frac{a^2}{6}+m^3\right)$
$x^2\left(9x+6-12x^3-18x^7\right)$
$4\cos\:2\theta+9=-14\cos\theta$
$\left(1\right)\left(5\right)-0.5\left(5.\right)$
$\tan^2a-\sec^2a$
$\left(4x-2\right)\cdot\left(4x+4\right)-\left(4x+3\right)^2$
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