$\sin\left(30\right)-\tan\left(60\right)^2+\cos\left(45\right)^2$
$\lim_{x\to0}\left(\frac{\frac{1}{x^2}-\frac{1}{\left(x+h\right)^2}}{h}\right)$
$\lim_{x\to\infty}\left(\frac{5}{-1+e^x}\right)$
$-2+5+4+5+4+-1+-2+-1$
$5.9\cdot1.5\cdot10^28$
$2m-3n-4n+4m-1+4m-8+5+12$
$\frac{x^9}{x^5}$
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