$\frac{dy}{dx}=\frac{2x^3-y}{2x}$
$\frac{dy}{dx}=8\left(x^2-1\right)$
$\frac{2n^6}{-3n^{-5}}$
$\frac{\sin^2x}{4-4\cos^2x}$
$\frac{\left(-6+108x\right)}{12}$
$\lim_{x\to\infty}\left(x\cdot tan\left(\frac{1}{x}\right)\right)$
$\int\left(2f^2-1\right)^2dx$
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