$7\:+\:12\:+\:-1\:+\:-2\:+\:10$
$\frac{216x^6-125}{6x^2-5}$
$y=x\left(2x-3\right)\left(2x+3\right)$
$\int\frac{2}{x^6}\:dx$
$\lim_{x\to\infty}x^2ln\:\left(1+\frac{3}{x^2}\right)$
$3\cdot sec^2x\cdot\left(1-sin^2x\right)$
$\frac{x}{x-1}+\frac{2}{x}=6$
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