$\lim_{x\to\infty}\left(\frac{x^3}{5e^{\left(\frac{x}{4}\right)}}\right)$
$\lim_{x\to0}\left(\frac{tan20x}{sin4x}\right)$
$x+y\cdot1$
$x^2+7x-18=0$
$\left(8+x\right)y'=2y$
$2^7\cdot2^8$
$0=2\log\:_e\left(x-2\right)-\log\:_e\left(x\right)$
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