Prove the identity
$\cot\left(x\right)\cdot\sec\left(x\right)=\csc\left(x\right)$
$\frac{\csc\left(x\right)}{\cot\left(x\right)}=\sec\left(x\right)$
$\tan\left(x\right)\cdot \cos\left(x\right)\cdot \csc\left(x\right)=1$
$\sin\left(x\right)^2+\cos\left(x\right)^2=1$
$\csc\left(x\right)\cdot\tan\left(x\right)=\sec\left(x\right)$
$\tan\left(x\right)+\cot\left(x\right)=\sec\left(x\right)\csc\left(x\right)$
$\frac{1-\sin\left(x\right)}{\cos\left(x\right)}=\frac{\cos\left(x\right)}{1+\sin\left(x\right)}$
Trigonometric Identities
2. See formulas
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