$\lim_{x\to-\infty}\left(\frac{\left(2x^4-3x\right)}{3x^5+2x^2}\right)$
$\left(2x^3\right)\left(6\right)$
$\lim_{x\to\infty}\left(\frac{2^{2^x}}{x^{log\left(x\right)}}\right)$
$\left(5x^3\:+\:6y^3\right)^2$
$x^2-4x>-3$
$-6x^2y+12x^2y$
$5\left(6x+4\right)$
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