$g\left(x\right)=\frac{x^3+5x}{x^5+3x^3-4x}$
$4.56\cdot10^8$
$\int\:x\left(1+y^2\right)dx$
$\frac{sin^2-tan^2}{cosc\:x}$
$6\left(x+5\right)^2\:-3\left(x+5\right)\:$
$\frac{x^3+5x^2-4x-20}{x+4}$
$\int_0^{\pi}\left(4x\sin\left(x\right)\right)dx$
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