$2,5+37,29+85,6$
$y'=\sec\left(x\right)+y\cdot\tan\left(x\right)$
$3.14159\cdot8\cdot8$
$x^2+14x-51=y$
$2+m=-18$
$\lim_{x\to\infty}\left(\frac{x^2+4}{2}\right)$
$\frac{x^3\:-\:16x^2\:-\:33x\:-\:18}{x\:-\:1}$
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