$\frac{tan\left(x\right)}{1-\sec^2\left(x\right)}=-\cot\left(x\right)$
$-5x\:+\:3\left(6\:+\:7x\right)$
$m^4n^3\sqrt[5]{\frac{32}{m^5n^{10}}}$
$\left(\frac{3}{2}+2x\right)^2$
$ln7x$
$\frac{x^4+81}{x^2+1}$
$\int-5x^4dx$
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