$\frac{sin\left(\frac{x}{2}\right)}{cos\left(\frac{x}{2}\right)}$
$\frac{3}{y}=\frac{6}{y-2}$
$\left(-8x-8^2\right)$
$\int tan^2\left(2x-2\right)dx$
$+1\:-\:\left(-51\right)-\left(-43\right)$
$\int\left(2x+7\right)\left(x^2+7x+6\right)^5dx$
$4x^2y^3-16xy^3z$
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