$\lim_{x\to0}\left(\left(\frac{x^2+2sin\left(x\right)}{x}\right)\right)$
$\frac{16x^2-8x+1}{4x-1}$
$\:xy\:+\:4xy\:$
$\left(2x-4\right)-\left(-3x+1\right)$
$\left(5a^{n+1}\right)\left(5a^{n+1}\right)$
$\left(4x-z\right)^3$
$4x\frac{1}{2}$
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