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The difference of two logarithms of equal base $b$ is equal to the logarithm of the quotient: $\log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right)$
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$\log_{5}\left(1\right)-\log_{5}\left(625\right)$
Learn how to solve expanding logarithms problems step by step online. Expand the logarithmic expression log5((1/625)). The difference of two logarithms of equal base b is equal to the logarithm of the quotient: \log_b(x)-\log_b(y)=\log_b\left(\frac{x}{y}\right). Evaluating the logarithm of base 5 of 1. x+0=x, where x is any expression. Decompose 625 in it's prime factors.