$\lim_{x\to0}\left(\frac{x^2+6}{x}\right)$
$\sqrt{8a^3}b$
$tan47.48=\frac{1}{cot\:\left(47.48\right)}$
$x-9\cdot72$
$\left(1-x\right)dy-y^2\:dx=0$
$\frac{dy}{dx}+e^xy=1$
$\frac{dy}{dx}+xy^3=0,\:y\left(0\right)=1\:$
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