$\left(\frac{2}{3}x^3-\frac{1}{2}\right)\left(\frac{2}{3}x^3-\frac{3}{2}\right)$
$\frac{3x^5+4x^3+5x-12}{x-2}$
$-2+5x^3+3y^2+4x^3-7+3-5x^3$
$\left(2p+3q\right)\left(4p-5q\right)$
$12x^2+19x+5=0$
$-14-7x$
$5+5x\left(-2\right)-18:\left(-2-4\right)$
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