$2x+x^2=6x$
$\int\left(\frac{64}{x^2\sqrt{16-x^2}}\right)dx$
$\lim_{x\to\infty}\left(1+x\right)^{\frac{1}{2}}$
$\sqrt[5]{33-1}$
$9ab+12bd-45ac-60cd$
$81x^3+81x^2-72x-72$
$\left(6x+24\right)\cdot\left(3x+12\right)$
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