$\left(x-3\right)\left(x^2+\frac{1}{3}\right)$
$\frac{2}{3}x+4\:\ge x+1$
$\left|50\cdot\left(-2\right)\right|\cdot9$
$\frac{d}{dx}\log10x$
$\int\left(e^{3x}\:8x^5\right)dx$
$20-2\cdot7+1-\left(-3\right)+10$
$\int\frac{x}{2x^2-6}dx$
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