$\frac{x^3+2x^2-5x+1}{x^2+2}$
$\frac{3+x^3-5x}{x^2+x}$
$\lim_{x\to\infty}\left(\frac{x^2-2x+3}{x^2-3x+2}\right)^{\frac{\sin\left(x\right)}{x}}$
$\:0,643+5$
$\left(x\:y^2\:z^3-\:3\:x^6\:y\:z\right)^2$
$y=x^{-4}$
$\left(x+1\right)\left(x-6\right)\left(x-31\right)$
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