$3x^3\:\:\:+\:x^3\:$
$xy'-xy=4y$
$\lim_{x\to\infty}\frac{\left(x-2\right)\left(x+1\right)}{x^2-2x+4}$
$1,4x-2,8y=1$
$-11x>10$
$sec\:x\:+\:csc\:x\:=\:sec\:x\:csc\:x\:\left(sen\:x\:+\:cos\:x\right)$
$\int\frac{5x^{3}-9x^{2}+8x-16}{x^{4}-6x^{2}+8x-3}dx$
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