$x^3+3x^2+4x=-y$

$\int\frac{2x^2+4}{x\left(x+4\right)\left(x+8\right)}dx$

$\sqrt[3]{25x^5}y^2\cdot\sqrt[3]{10x^6}y^8$

$\frac{1}{sec\left(x+1\right)}+\frac{1}{sec\left(x-1\right)}$

$-4k-108-xk=-4k-18\left(6+10k\right)$

$\lim_{x\to\infty}\left(\frac{ln\:1+\frac{8}{x}}{\frac{1}{6x}}\right)$

$100-16x^2$