$\int\frac{\left(1\right)}{\left(x+2\right)\left(x-2\right)}dx$
$\frac{\left(12a^4b^6c^2\right)}{8ab^3c^0}$
$3y^2+12y$
$2y^3-7x^2=5$
$\frac{x^4-6x^3+8x^2+12}{x-4}$
$y^2-3y+1$
$\frac{dy}{dx}=\left(4x+3\right)\left(y+1\right)$
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